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A car went 60 km in 5/6 of an hour while a second car went 54 km in 2/3 h. Which car was faster? How many times faster?
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Respuesta :

gustanika
This is the relationship between distance, velocity and time
v = d/t

To find which car was faster, we need to find the velocity
First car
d = 60 km
t = 5/6 of an hour

Calculate the velocity of the first car
v = d/t
v = 60 ÷ 5/6
v = 60 × 6/5
v = 72
The velocity of the first car is 72 km/hour

Second car
d = 54 km
t = 2/3 of an hour

Calculate the velocity of the second car
v = d/t
v = 54 ÷ 2/3
v = 54 × 3/2
v = 81
The velocity of the second car is 81 km/hour

81 is bigger than 72. The second car was more faster

81 - 72 = 9 km/hour
The second car was 9 km/hour faster than the first car
This is the relationship between distance, velocity and timev = d/t
To find which car was faster, we need to find the velocityFirst card = 60 kmt = 5/6 of an hour
Calculate the velocity of the first carv = d/tv = 60 ÷ 5/6v = 60 × 6/5v = 72The velocity of the first car is 72 km/hour
Second card = 54 kmt = 2/3 of an hour
Calculate the velocity of the second carv = d/tv = 54 ÷ 2/3v = 54 × 3/2v = 81The velocity of the second car is 81 km/hour
81 is bigger than 72. The second car was more faster
81 - 72 = 9 km/hourThe second car was 9 km/hour faster than the first car
 Read more on Brainly - https://brainly.com/sf/question/8668399

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