Respuesta :
Answer : The final temperature of iron block will be 91 degree celcius.
Explanation:
Heat released during condensation of water = Heat absorbed by iron block
[tex]Q= n\times\Delta H_{vap}[/tex]
Q= heat absorbed or released
n = number of moles
[tex]DeltaH_{vap}= enthalpy of vaporisation[/tex]
[tex]\text{no of moles}= \frac{given mass}{Molecular mass}[/tex]
[tex]\text{no of moles}=\frac{0.95g}{18gmole^{-1}}[/tex]
= 0.053 moles
[tex]Q= 0.053mole\times44.0kJmole^{-1}[/tex]
= 2.322 kJ = 2322 Joules
[tex]Q=m\times c\times Deltat[/tex]
[tex]\text{Heat absorbed by iron block}=m\times c\times\Delta t[/tex]
m = mass of substance
c = specific heat capacity
[tex]\Deltat[/tex]=change in temperature
[tex]2322=75g\times0.450J/g^0C\times{T_{final}-T_{initial}}[/tex]
[tex]2322=75\times0.450\times{T_{final}-22}[/tex]
[tex]T_{final}=91^0C[/tex]
The final temperature of a block of iron whose mass is 75.0 g that was initially at 22 °C after gaining heat during condensation of water of mass 0.95 g is 90.8 °C.
Further Explanation:
Heat capacity
- Heat capacity refers to the amount of heat that is required to raise the temperature of an object or a substance by one degree Celsius or 1 Kelvin.
- Heat capacity is thus expressed as Joules/°C
Specific heat capacity
- This is the amount of heat that is required to raise the temperature of a unit mass of a substance by 1 degree Celsius or 1 Kelvin.
- It is expressed as Joule/kg/°C or J/g/°C. For example the specific heat of water is 4.184 j/g/°C
Quantity of Heat
- Quantity of Heat is calculated using the formula;
Q = mCΔT
Where Q is the Quantity of heat, m is the mass of the object, C is the specific heat capacity of the object and ΔT is the resulting change in temperature.
- ΔT is given by the difference between initial temperature and final temperature.
That is; ΔT = Tfinal - Tinitial
In this Question;
Heat released during condensation is equivalent to the heat absorbed by iron block.
Step 1; Moles of water
1 mole of water is 18.0 g/mol
Thus; number of moles = 0.95 g/18 g/mol
= 0.053 moles of water
Step 2: Heat released during condensation
Heat released during condensation = Number of moles x Latent heat of vaporization
Q = 0.053 moles x 44.0 kJ/mol
= 2.322 Kj
Step 3: Heat gained by Iron block and change in temperature
Q = mCΔT
m = 75 g
c = 0.450 J/g/°C
Therefore;
Q = 75 g x 0.450 J/g/°C x ΔT
2322 J = 75 g x 0.450 J/g/°C x ΔT
ΔT = 68.8°C
Step 4; Calculating final temperature
ΔT = Tfinal - Tinitial
Initial temperature = 22°C
Final temperature = initial temperature + Change in temperature
= 68.8 + 22
= 90.8 °C
Keywords: Change in temperature, Specific heat capacity, Quantity of heat
Learn more about;
- Specific heat capacity: https://brainly.com/question/4759369
- Heat capacity: https://brainly.com/question/4759369
- Quantity of heat calculation example: https://brainly.com/question/4759369
Level: High school
Subject; Physics
Topic: Quantity of Heat
