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The electric field midway between two equal but opposite point charges is 386 n/c, and the distance between the charges is 16.0 cm. what is the magnitude of the charge on each?

Respuesta :

Kalahira
We'll use the following formular E = Kq / r^2 Since the electric field is 386 N/C midway between the charges, r = 1/2 * 16 = 8 cm = 0.08m. So we have 386 = (8.998 * 10^(9) * q) / (0.08)^2 386 * 0.0064 = 8.998 * 10^(9) * q q = (386 * 0.0064)/ 8.998 * 10^(9) q = 2.4704/ 8.998 * 10^(9) q = 2.754 * 10^(-10)

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