Here the line passes through (0,0) and (1,3).
First we need to find the slope , and for that we need to use the following formula
[tex] m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} [/tex]
On substituting the values from the point, we will get
[tex] m=\frac{3-0}{1-0}=3 [/tex]
Now we will use slope intercept form, which is
[tex] y = mx+ b [/tex]
Where m is the slope and b is the y intercept
And on substituting the values of x and y from the point (1,3) and slope, m = 3, we will get
[tex] 3 = 3(1)+b [/tex]
[tex] 3=3+b [/tex]
b =0
Substituting the values of m and b in the slope intercept form, we will get
[tex] y= 3x [/tex]
