Respuesta :

[tex]f(x)=x^2-1[/tex]
[tex]g(x)=2x-3[/tex]

[tex]f\circ g(x)=f(g(x))=f(2x-3)=(2x-3)^2-1=4x^2-12x+8[/tex]

which is a polynomial, so the domain is [tex](-\infty,\infty)[/tex].

Answer:

A

Step-by-step explanation: