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A certain preparation requires liquids x, y, and z in the proportion 5:2:1. how many gallons of the preparation can be made from 25 gallons of x, 20 gallons of y, and 8 gallons of z

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madkminecraft
5 because 25 gallons of x 20 gallons of y and 8 gallons of z and if you used you cant make 8 gallons of the preparation because you can only have 5 gallons of x so your answer is 5 

The total gallons is 40.

The given ratio of x,y, and z =5:2:1

So, 25 gallons of liquid be x

20 gallons of liquid be y

8 gallons of liquid be z

Since, we have to maintain the ration 5:2:1 then,

[tex]x:y:z=5:2:1[/tex]

Then,

[tex]x=5a\\y=2a\\z=a=8[/tex]

Substitute  the value of [tex]a[/tex] we get,

[tex]x=5\times 8\\x=40\\y=20\times8\\y=16[/tex]

Now, as we know that the maximum is 25 gallons for x we can use.

So, the ratio of x be either equal to 25 or less than 25

So, take a=5 that is z=5

Then the ratio becomes,

x:y:z=25:10:5

Hence, the total gallon is,

25+10+5=40

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