Respuesta :
H=RTI²k where k is a constant.
1200=8×2×64k=1024k, so k=1200/1024=75/64.
So 6000=R×5×100×75/64=9375/16 and R=6000×16/9375=10.24 ohms.
1200=8×2×64k=1024k, so k=1200/1024=75/64.
So 6000=R×5×100×75/64=9375/16 and R=6000×16/9375=10.24 ohms.
Answer:
Value of resistance should be 4 ohm
Explanation:
Since heat developed in a current carrying wire is given by
[tex]H=I^{2}RT[/tex]
where I=Current in wire , R= Resistance of wire , T = Time for which current has flown
Case-I
[tex]H_1=I_1^{2}R_1T_1[/tex]
where  [tex]H_1=1200 units, R_1= 8 ohm , I_1= 5 amp,T_1= 2min[/tex]
Case-II
[tex]H_2=I_2^{2}R_2T_2[/tex]
where [tex]H_2=6000 units, R_2= ? ohm , I_2= 10 amp,T_2= 5min[/tex]
From case-I and case-II
[tex]R_2=\frac{H_2I_1^{2}R_1T_1}{I_2^{2}T_2H_1}[/tex]
=>[tex]R_2=\frac{6000\times 5^{2}\times 8\times 2}{10^{2}\times 5\times 1200} ohm=4ohm[/tex]
=>[tex]R_2=4ohm[/tex]
Thus the similar wire must have 4 ohm resistance to develop 6,000 heat units with a current of 10 amps in 5 minutes
