The value of y of the given rectangle is; y = 7
We are told that ABCD is a rectangle.
We are given;
AC = 6y − 1
AC = 6y − 1 BD = 4y + 13
AC and BD are diagonals of the rectangle and we know that diagonals of a rectangle are equal. Thus;
6y − 1 = 4y + 13
Rearranging we have;
6y - 4y = 13 + 1
2y = 14
y = 14/2
y = 7
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