Respuesta :
Assuming independence of the two events, the probability that both events will happen is the product of the two individual probabilities.
P(Anuj away ∩ Ben is late) = 70%*6% = 0.042
P(Anuj away ∩ Ben is late) = 70%*6% = 0.042
Answer:
Probability that Anuj is away and Ben is late is:
0.018
Step-by-step explanation:
A: Anuj is away i.e. he will not be in the class
P(A)=30/100 (30% he will not be in the class)
B: Ben is late
P(B)=6/100 (6% he will be late)
A∩B: Anuj is away and Ben is late
Events A and B are independent
So, P(A∩B)=P(A)×P(B)
= [tex]\dfrac{30}{100}\times \dfrac{6}{100}[/tex]
= 0.018
So, probability that Anuj is away and Ben is late is:
0.018