Looking at the problem, we can say that this is a problem involving ideal gas equation. We are given 2 data for pressure and one volume. Assuming that the temperature for both cases is the same, we can use Boyle's Law to find the pressure.
P₁V₁ = P₂V₂
(100 kPa)(7100 mL) = (P₂)(492 mL)
Solving for P₂,
P₂ = 1,443.09 kPa