Respuesta :

Ok so we know:
The initial velocity (u) is 20m/s
The acceleration (a) is 4m/s2
The time taken (t) is 10 seconds.

We want to find 'r', the displacement/distance travelled during this period.

So we can use the equation:
[tex]r = ut + \frac{1}{2} a {t}^{2} [/tex]
So:
[tex]r = 200 + 200[/tex]
So r is 400 metres.

So the train moved 400m during this time.

Hope this helped

Distance cover by train is 400 meter.

Given that;

Initial velocity of train = 20 m/s

Acceleration of train = 4 m/s²

Time taken = 10 seconds

Find:

Distance cover by train

Computation:

Using second equation of motion

S = ut + (1/2)at²

S = 20(10) + (1/2)(4)(10²)

S = 20(10) + (2)(100)

S = 200 + 200

S = 400 meter

Learn more:

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