80 ft^2
Looking at the figure, you can easily determine that it's made of two separate figures, a rectangle that's 2 feet by 16 feet, and a triangle that has sides of 16 feet, 10 feet, and 10 feet. The triangle can then be divided into two right triangles with a hypotenuse of 10 feet and one leg of 8 feet, so you can use the Pythagorean theorem to calculate the other leg (which is also the height of the large triangle mentioned above). That value is sqrt(10^2 - 8^2) = sqrt(100 - 64) = sqrt(36) = 6.
So we now know that the large 16,10,10 triangle has a base of 16 and a height of 6. So let's calculate the area of the entire figure.
A = 2*16 + 16*6/2
A = 32 + 16*3
A = 32 + 48
A = 80
So the area of the entire figure is 80 square feet.
