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The height of an arrow shot upward can be given by the formula s = v0t - 16t2, where v0 is the initial velocity and t is time. How long does it take for the arrow to reach a height of 48 ft if it has an initial velocity of 96 ft/s? Round to the nearest hundredth. The equation that represents the problem is 48 = 96t - 16t2. Solve 16t2 - 96t + 48 = 0.

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tkmaplethorpepaykzs

.55 first and then 5.45 you find it by finding the square root of six and finding it to be negative or positive on the right side of the equation

.55 & 5.45

Answer:

[tex]t = 0.56 s\\[/tex]

Step-by-step explanation:

The given equation is

[tex]s = v_{0} t - 16t^{2} \\48 ft = 96 \frac{ft}{s} t- 16t^2\\\\16t^2 -96t + 48 =0\\t^{2} - 6t + 3 = 0\\t = 0.56\\[/tex]

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