the vertex is at (0, 3) so y=a(x-0)²+3, which is y=ax²+3
next, use a given point to find a: 10=a(3)²+3, so 9a=7, a=7/9
the equation is then y=[tex] \frac{7}{9}x^2+3 [/tex]
as for the first question, the shape is an ellipse, the domain is -5≤x≤5, the range is -3≤y≤3
the equation can be written as :[tex] \frac{x^2}{25}+ \frac{y^2}{9} =1[/tex]
