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An energy of 434 kj/mol is required to cause a chromium atom on the metal's surface to lose an electron. calculate the lowest frequency of light that can ionize a chromium atom.

Respuesta :

meerkat18
The working equation for this is written below:

E = hv
where
h is Planck's constant = 6.62607004×10⁻³³ m²·kg/s
v is the frequency

Let's convert the units of energy to SI units:

E = 434 kJ/mol (1,000 J/1 kJ)(1 mol/52 g)(1000 g/1 kg)
E = 4.34×10⁷ J/kg = hv = (6.62607004×10⁻³³ m²·kg/s)(v)
Solving for v,
v = 6.55×10³⁹ s⁻¹

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