Respuesta :

nobillionaireNobley
Part 1:

Given a number line with the point [tex]\bar{x}=3.8 [/tex] and the point [tex]\mu=4.27[/tex]

The sampling error is given by:

[tex]\bar{x}-\mu=3.8-4.27=-0.47 [/tex]



Part 2:

Given a number line with the point [tex]\bar{x}=26.43 [/tex] and the point [tex]\mu=24.67[/tex]

The sampling error is given by:

[tex]\bar{x}-\mu=26.43-24.67=1.76 [/tex]
MrRoyal

The sampling error from the number line is 1.58

From the number line (see attachment), we have the following parameters:

  • Sample Mean: [tex]\bar x = 26.72[/tex].
  • Population Mean: [tex]\mu = 25.14[/tex].

The sampling error (E) is the difference between the sample mean and the population mean.

So, we have:

[tex]E = \bar x - \mu[/tex]

This gives

[tex]E = 26.72 - 25.14[/tex]

Evaluate the difference

[tex]E = 1.58[/tex]

Hence, the sampling error is 1.58

Read more about sampling error at:

https://brainly.com/question/19264268

Ver imagen MrRoyal

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