Part A:
Given that Nicholas's school is located at point (3, 2) and that the post office is located at point (-2, -2), then the distance between Nicholas's school and the post office is given by:
[tex]d= \sqrt{(-2-3)^2+(-2-2)^2} \\ \\ = \sqrt{(-5)^2+(-4)^2} = \sqrt{25+16} \\ \\ \sqrt{41} =\bold{6.4} \ units[/tex]
Part B:
If Nicholas is located at point (– 3 , 2), the distance to get to the grocery store located at point (1,-1) is given by:
[tex]d= \sqrt{(1-(-3))^2+(-1-2)^2} \\ \\ = \sqrt{(1+3)^2+(-3)^2} = \sqrt{(4)^2+9} \\ \\ = \sqrt{16+9} = \sqrt{25} =\bold{5} [/tex]
