Answer: Number of moles of ions in 0.716 L of 0.450 M solution is 1.2888 moles.
Solution:
[tex]Na_3PO_4(aq)\rightarrow 3Na^+(aq)+PO_4^{3-}(aq)[/tex]
Volume of the solution 716 mL
Molarity of the solution : 0.450 M
[tex]Molarity=\frac{\text{Number of moles}}{\text{Volume in Liters}}[/tex]
[tex]0.450 mol/L=\frac{\text{Number of moles of }Na_3PO_4}{0.716 L}[/tex]
[tex]\text{Number of moles of }Na_3PO_4=0.450mol/L\times 0.716=0.3222 moles[/tex]
According to reaction one mol [tex]Na_3PO_4[/tex] is giving 4 moles of ions.
Number of moles of ions in 0.716 L of 0.450 M solution is = [tex]4\times 0.3222=1.2888 moles[/tex]
Hence,number of moles of ions in 0.716 L of 0.450 M solution is 1.2888 moles.
