Respuesta :
The answer is F2, it has the boiling point that is closest to Argon.
Cl2 is a molecule that is larger than F2 so it has larger london dispersion forces than F2 and NaF has high boiling point as it is an ionic compound and HCl and Hf both also have high boiling point. Argon has very low boiling point so F2 has the boiling point that is closest to the Argon.
Cl2 is a molecule that is larger than F2 so it has larger london dispersion forces than F2 and NaF has high boiling point as it is an ionic compound and HCl and Hf both also have high boiling point. Argon has very low boiling point so F2 has the boiling point that is closest to the Argon.
Chlorine has higher inter-molecular interaction or London dispersion force. The Florine molecule has the has a boiling point closest to that of Argon.
Boiling Point:
It is the temperature of the substance at which vapor pressure e of the liquid is equal to the pressure surrounding the liquid. At this point liquid start converting to vapor.
Ar is -185.8 [tex]\rm \bold{^oC}[/tex]
[tex]\rm \bold{F_2 = -188 ^oC}[/tex]
[tex]\rm \bold { Cl_2= -34.67^oC}[/tex]
[tex]\rm \bold { HCl = -85.05 ^oC}[/tex]
[tex]\rm \bold {HF = 19.5 ^oC}[/tex]
Here, Chlorine molecule has larger size than Florine molecule. Hence, In Chlorine has higher inter-molecular interaction or London dispersion force.
HCl and HF is are ionic molecule hence, have higher boiling point than Ar.
Hence, we can conclude that the Florine molecule has the has a boiling point closest to that of Argon.
To know more about boiling point, refer to the link:
https://brainly.com/question/2153588
