From n = 5, the electron can drop to n = 4, 3, 2, 1 . Thus, there will be 4 possibilities
Now, the electron that dropped to n = 4 can drop to n = 3, 2, 1. This will give 3 possibilities
The electron at n = 3, can drop to n = 2, 1. This gives 2 possibilities
Finally, the electron at n = 2 can drop to n=1. This gives 1 possibility
Thus in total the number of ways in which the electron can de-excite is :
4+3+2+1 = 10
10 different wavelengths of light can be emitted as the electron loses energy from n = 5 level
There are four different wavelengths of light that can be emitted as this excited atom loses energy
According to the Bohr model of the atom, an electron in an atom absorbs energy and moves from a lower to a higher energy level. The energy associated with such transition is equal to the difference in energy between the two energy levels.
If an electron in hydrogen atom has been excited to energy level n =5, the following transitions are possible;
n = 5 ----> n =4
n =5 ------> n =3
n = 5 -----> n = 2
n = 5 ----> n = 1
Hence, there are four different wavelengths of light that can be emitted as this excited atom loses energy.
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