Respuesta :
Using only the values given in the table for the function , f(x) = x3-3x-2 , what is the interval of x-values over which the function is decreased. Advertisement ... 3 = 3(x² - 1) We know, any Function f(x) decrease s in interval [a, b] when f'(x) < 0 ... -1 < x < 1. Hence, function f(x) = x³ - 3x - 2 , is decreased in (-1, 1).
The interval of x-values over which the given function is decreasing is (-1,1) and this can be determined by differentiating the given function.
Given :
[tex]\rm f(x) = x^3-3x-2[/tex]
The following steps can be used in order to determine the interval in which the given function is decreasing:
Step 1 - Write the given function.
[tex]\rm f(x) = x^3-3x-2[/tex]
Step 2 - Now, differentiate the above function with respect to 'x'.
[tex]\rm f'(x) = 3x^2-3[/tex]
Step 3 - Now, equate the above expression to zero.
[tex]\rm x^2 = 1[/tex]
x = 1 or -1
Therefore, the correct option is C).
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https://brainly.com/question/24062595
