Answer:
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Question 1) : The answer is: " f(2) = 5 " .
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Given the quadratic function:
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" f(x) = x² + 1 " ;
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FInd the value of: " f(2) " ; that is, when "x = 2" ; what is the resulting value?
So, replace all values of "x" in the function with "2" ; and solve to find the "output" ;
f(2) = (2)² + 1 = (2 * 2) + 1 = 4 + 1 = 5 .
The answer: f(2) = 5 .
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Question 2):
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Given: " f(x) = x² − 3x² + 2 " ; Find: "f(3)" ; that is, when "x = 3" ; what is the resulting value?
So; replace all values of "x" in the function with "3" ; and solve to find the "output" ;
f(3) = (3)² − 3(3²) + 2 ;
= 9 − (3)(9) + 2 ;
= 9 − 27 + 2 ;
= (9 − 27) + 2 ;
= - 18 + 2 ;
= -16 .
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The answer is: f(3) = - 16 .
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Hope these explanations ar of some help.
