contestada

The density of gold is 19.3 g/cm3. A piece of gold displaces 2 mL of water. The specific gravity of gold is:

A.19.3
B.38.6
C.9.6
D.0.10

Respuesta :

The answer to this is 19.3

Answer:

A) 19.3

Explanation:

As we know that specific gravity is defined as the ratio of weight of the object and weight of the water displaced by the object

so it is given by

[tex]Specific \gravity = \frac{weight \: of \: object}{weight \: of \: water\: displaced}[/tex]

now we have

weight of the object = (density)(volume)g

weight of object = [tex](19.3 g/cm^3)(2 mL)g[/tex]

now weight of the liquid displaced is given by

weight of water displaced = [tex](1 g/cm^3)(2 mL)g[/tex]

now we have

specific gravity = [tex]\frac{(19.3)(2mL)g}{(1)(2 mL)g}[/tex]

specific gravity = 19.3