Answer:
[tex]6+2^{1}=8 \Rightarrow 6+2=8 \Rightarrow 8=8[/tex]
Step-by-step explanation:
1) One solution is to write, as our exponent:
[tex]2^{1}=2[/tex]
2) Because this is special case of the Exponents Law, valid for every base ≠ 0.
[tex]a^{1}=a[/tex]
3) Hence, including an exponent the numbers 6, 2 whose value is eight.
[tex]6+2^{1}=8 \Rightarrow 6+2=8 \Rightarrow 8=8[/tex]
Therefore our expression is true
