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An aircraft engine takes in 9000 j of heat and discards 6400 j each cycle. (a) what is the mechanical work output of the engine during one cycle? (b) what is the thermal efficiency of the engine?

Respuesta :

work done = heat in - heat out 
= 9000 -6400 = 3600 J per cycle. 

And the efficiency = work out / heat in 
= 3600/9000 
= 0.4 or 40%

Sorry if this does not help.
Lanuel

a. The mechanical work output of the engine during one cycle is 2600 Joules.

b. The thermal efficiency of the engine is equal to 28.89%.

Given the following data:

  • Heat input = 9000 Joules
  • Heat output = 6400 Joules

a. To determine the mechanical work output of the engine during one cycle:

Mathematically, the mechanical work output of an engine during one cycle is given by the formula:

[tex]Work = H_{in}- H_{out}\\\\Work = 9000-6400[/tex]

Work output = 2600 Joules

b. To determine the thermal efficiency of the engine:

[tex]Th_{E} =\frac{Work}{H_{in}} \times 100\\\\Th_{E} =\frac{2600}{9000} \times 100\\\\Th_{E} =0.2889 \times 100[/tex]

Thermal efficiency = 28.89%

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