In this solution we will need two steps, 1) calculate the heat required to get water to the temp of 100 C and 2) find the latent heat of vapourization required.
First, change the 11.8g to kg: = 0.0118kg
Equations: Q = mcT, Q=mL
c for water = 4186 J/(kg C)
L for water = 22.6 x 10^5 J/kg
1) Q = mcT
Q = 0.0118 kg x 4186 J/(kg C) x (100 C - 65.5 C)
Q = 1704.12 J
2) Q = mL
Q = 0.0118 kg x 22.6 x 10^5
Q = 26668 J
Qf = 1704.12J + 26668J
Qf = 28372.12J
With sig figs: 2.84 x 10^4 J
