If 2x+y=5, then y=5-2x, so she substituted correctly.
x+4x=5x, so she combined like terms correctly.
She didn't subtract 10 from both sides, she added 10 to both sides.
Check the solution:
[tex]2x+y=5 \hbox{ and } x-2y=10 \\
2 \times 4-3=5 \hbox{ and } 4-2 \times (-3)=10 \\
8-3=5 \hbox{ and } 4+6=10 \\
5=5 \hbox{ and } 10=10 \\
\checkmark[/tex]
The answer is: She made no mistake.