Respuesta :

In this question, there are 500 people in the population and the amount of hba allele is 250. Each person should have 2 alleles since a chromosome is coupled. So, the total allele in 500 people should be: 500*2 allele= 1000 allele.
Then frequency of the allele should be:250 allele / 1000 allele = 0.25 = 25%

A variant form of a gene is called an allele. They are different characters located on the same gene or loci of a chromosome.

  • They contribute to the phenotypic characteristics of an organism and can be either recessive or dominant.

  • Gene variation in the community or the population is called allele frequency.

  • Allele frequency can be calculated by dividing the number of times the allele of interest is observed in the sample by the total number of copies of that allele.

Given,

  • Total number of population = 500

  • Hba allele present in the population = 250

  • Every person has two alleles for a character hence, the number of alleles present in the total population = 500 × 2 = 1000

  • [tex]\text{Allele frequency} & = \dfrac{250}{1000}[/tex]

       = 0.25

       = 25 %

Therefore the frequency of Hba allele in a population of 500 is 25 %.

To learn more about allele frequency refer to the link:

https://brainly.com/question/202249

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