The answer: x = 200 .
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Explanation:
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Given the equation:
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(1/5)x - (2/3)y = 30 ;
What is the value of "x" when "y" = 15 ?
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Plug in "15" for "y" into the equation; and solve:
(1/5)x - (2/3)*15 = 30 ;
Note: [tex] \frac{2}{3}*( \frac{15}{1}) = \frac{2*15}{3*1} = \frac{30}{3} = 10 ;
[/tex]
OR: [tex] \frac{2}{3} * \frac{15}{1} = ? ;
The "3" cancels out to a "1" ; and the "15" cancels out and is replaced with a "5" ; since; "(15÷3=5") ; and since: "(3÷3=1)" ; and we have:
[tex] \frac{2}{1} * \frac{5}{1} = \frac{2*5}{1*1} = \frac{10}{1} = 10 ;
[/tex]
Or: [tex] \frac{2}{1} * \frac{5}{1} = 2 * 5 ; (since 2/1 = 2; and since 5/1 = 6 ;
→ 2 * 5 = 10 ;
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So, we can rewrite the equation:
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(1/5)x - (2/3)y = 30 ; and replace "(2/3)y" with "10") ;
(1/5)x - 10 = 30 ;
Add "10" to EACH SIDE of the equation;
(1/5)x - 10 + 10 = 30 + 10 ;
to get: (1/5)x = 40 ;
Now, multiply EACH SIDE of the equation by "5" ; to isolate "x" on one side of the equation ; and to solve for "x" ;
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5* (1/5)x = 40 * 5 ;
x = 200 ;
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The answer: x = 200 .
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