You would not have enough pencils to equally distribute into equal piles.
You would always have a remainder.
This is because there are no two numbers that multiply and equal 43.
Accept 43 x 1 as stated in the question.
Good Luck! <3
Answer:
No, it is not possible.
Step-by-step explanation:
We have been given that you have 43 pencils. We are asked to find whether it is possible that besides 1 group of 43 pencils can we divide the pencils into groups with the same number of pencils with no pencils left over.
We know that 43 is a prime number and it has only two factors that are 1 and 43, so it is only divisible by 1 and 43.
Therefore, it is not possible to divide the pencils into groups with the same number of pencils with no pencils left over.
