Respuesta :
48.60g Mg x (1 mol Mg /24.3g Mg) x (6.02x10^23) = 1.20x10^24
Answer: [tex]1.204\times 10^{24} atoms[/tex] of magnesium are present 48.60 grams of magnesium.
Explanation:
Molar mass of the magnesium = 24.30 g/mol
Given mass of the magnesium = 48.60 g
[tex]moles=\frac{\text{Given mass}}{\text{molar mass}}[/tex]
Moles of magnesium = [tex]\frac{48.60 g}{24.30 g/mol}=2 mol[/tex]
[tex]1 mol=6.02\times 10^{23} atoms[/tex]
Number of a magnesium atoms in 2 moles:
[tex]2\times 6.02\times 10^{23}=1.204\times 10^{24} atoms[/tex]
[tex]1.204\times 10^{24} atoms[/tex] of magnesium are present 48.60 grams of magnesium.