Respuesta :
D=m/v where D=density, m=mass and v=volume
0.788=35/v
0.788v=35
v=35/0.788
v=44.4162436548
0.788=35/v
0.788v=35
v=35/0.788
v=44.4162436548
The volume of acetone is [tex]\boxed{0.0444{\text{ c}}{{\text{m}}^3}}[/tex].
Further Explanation:
Properties of any substance can either be intensive or extensive.
Intensive properties are the ones that depend on the nature of the substance, not on the size of the system. These properties remain the same even if the system is further divided into a number of subsystems. Examples of intensive properties are temperature, refractive index, molarity, concentration, pressure, and density.
Extensive properties are those that depend on the amount of the substance. These properties are additive in nature if a single system is divided into many subsystems. Examples of extensive properties are mass, enthalpy, volume, energy, size, weight, and length.
The ratio of mass to the volume of the substance is known as density. It is usually denoted by [tex]{{\rho }}[/tex]. The density of a substance is calculated by the following formula:
[tex]{\text{Density of substance}} = \dfrac{{{\text{Mass of substance}}}}{{{\text{Volume of substance}}}}[/tex] …… (1)
Rearrange equation (1) to calculate the volume of the substance.
[tex]{\text{Volume of substance}} = \dfrac{{{\text{Mass of substance}}}}{{{\text{Density of substance}}}}[/tex] …… (2)
The mass of the substance is to be converted into g. The conversion factor for this is,
[tex]1{\text{ mg}} = {\text{1}}{{\text{0}}^{ - 3}}{\text{ g}}[/tex]
So the mass of the substance is calculated as follows:
[tex]\begin{aligned}{\text{Mass of substance}}&= \left( {{\text{35 mg}}} \right)\left( {\frac{{{{10}^{ - 3}}{\text{ g}}}}{{1{\text{ mg}}}}} \right)\\&= 0.035{\text{ g}}\\\end{aligned}[/tex]
Substitute 0.035 g for the mass of the substance and [tex]0.788{\text{ g/c}}{{\text{m}}^3}[/tex] for density of substance in equation (2) to calculate the volume of acetone.
[tex]\begin{aligned}{\text{Volume of acetone}}&= \frac{{0.035{\text{ g}}}}{{0.788{\text{ g/c}}{{\text{m}}^3}}}\\&=0.0444{\text{ c}}{{\text{m}}^3}\\\end{aligned}[/tex]
Learn more:
- The major contribution of Antoine Lavoisier to chemistry: https://brainly.com/question/2500879
- Example of physical change: https://brainly.com/question/1119909
Answer details:
Grade: High School
Subject: Chemistry
Chapter: Density
Keywords: density, mass, volume, acetone, [tex]0.788 g/cm^3[/tex], 0.0444 cm^3, 0.035 g, intensive, extensive.
