A baseball team bought candy bars to celebrate a victory. The cost of 9 snickers and 6 butterfingers was $11.10 A Snickers cost $0.15 more than a Butterfinger. What was the price of each?

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Answer:

Snickers bar: $0.80

Butterfinger bar: $0.65

Step-by-step explanation:

Let's set up a system of equations to solve for the prices of a Snickers bar (x) and a Butterfinger (y) based on the given information.

Define the Variables:

Let:

  • x = price of a Snickers bar (in dollars)
  • y = price of a Butterfinger bar (in dollars)

Translate the Given Information into Equations:

We have two pieces of information from the problem:

  • The total cost of 9 Snickers and 6 Butterfingers is $11.10.
  • The cost of a Snickers bar is $0.15 more than the cost of a Butterfinger bar.

Therefore, we can write two equations based on these facts:

Equation 1: Total Cost

[tex] 9x + 6y = 11.10 [/tex]

Equation 2: Price Difference

[tex] x - y = 0.15 [/tex]

[tex] x = y + 0.15 [/tex]

Substitute Equation 2 into Equation 1:

Substitute x = y + 0.15 from Equation 2 into Equation 1:

[tex] 9(y + 0.15) + 6y = 11.10 [/tex]

Simplify and Solve for y:

Expand and simplify the equation:

[tex] 9y + 1.35 + 6y = 11.10 [/tex]

[tex] 15y + 1.35 = 11.10 [/tex]

Subtract 1.35 from both sides:

[tex] 15y = 11.10 - 1.35 [/tex]

[tex] 15y = 9.75 [/tex]

Divide both sides by 15 to solve for y:

[tex] y = \dfrac{9.75}{15} [/tex]

[tex] y = 0.65 [/tex]

Find x Using y:

Substitute y = 0.65 back into Equation 2 to solve for x:

[tex] x = 0.65 + 0.15 [/tex]

[tex] x = 0.80 [/tex]

Conclusion:

Therefore, the price of a Snickers bar (x) is [tex]\boxed{0.80} [/tex] dollars, and the price of a Butterfinger bar (y) is [tex]\boxed{0.65}[/tex] dollars.

Hence, a Snickers bar costs $0.80, and a Butterfinger bar costs $0.65.