a) To find where the rose lands, we set \( y = 0 \) in the equation \( y = 4x - x^2 \), yielding \( x^2 - 4x = 0 \). Factoring, we get \( x(x - 4) = 0 \), giving \( x = 0 \) and \( x = 4 \). So, the rose lands at \( x = 0 \) (where Romeo is) and \( x = 4 \).
b) For \( x = 4 \), we find \( y = 0 \) by plugging into the equation, resulting in \( y = 4(4) - 4^2 = 0 \). Since \( y = 0 \), the rose lands right at the base of the balcony, not passing over the 1m high wall. Hence, it does not pass over the wall.
