from a point S due south, the angle of elevation on the top of a vertical mast is 38 degrees, From another point W due west of mast is 28 degrees. If the mast is 50m high, calculate the distance between point, S and W to 2 decimal place

Respuesta :

Answer:

  113.75 m

Step-by-step explanation:

You want the distance between two observation points if the point S directly south sees the top of a 50 m mast at an elevation of 38°, while the point W directly west sees it at an elevation of 28°.

Tangent

The tangent relation can be used to find the distance from each observation point to the base of the mast.

  Tan = Opposite/Adjacent

Here, the sides of the right triangle modeling the elevation are ...

  Opposite = mast height = 50 m

  Adjacent = distance to mast

  tan(elevation angle) = (50 m)/(distance to mast)

South

The distance from the south observation point to the mast is about ...

  tan(38°) = (50 m)/s

  s = (50 m)/tan(38°) ≈ 63.997 m

West

Similarly, the distance from the west observation point to the mast is about ...

  w = (50 m)/tan(28°) ≈ 94.036 m

Between

The distance between these observation points is the hypotenuse of a right triangle on the ground with its right angle at the mast. It can be found using the Pythagorean theorem:

  s² + w² = d²

  d = √(63.997² +94.036²) ≈ 113.75

The distance between points S and W is about 113.75 meters.

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Additional comment

In the attachment, we have flattened the geometry so we could draw it on an x-y plane. The triangles SOMs and WOMw actually lie in vertical planes with OM being a vertical segment in the +z direction. Even though we have rotated these triangles to the x-y plane, the distances OS and OW remain the same, as does the distance SW.

The calculator display in the second attachment shows the distance calculated as the length of a vector with orthogonal components 50/tan(38°) and 50/tan(28°). This gets the result with about the least number of keystrokes.

Ver imagen sqdancefan
Ver imagen sqdancefan

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