A 67 kg skier is at the top of a 27 m hill at rest. What is their velocity when they reach the bottom of the hill in m/s? Round to the nearest 100th

To find the velocity of the skier when they reach the bottom of the hill, we can apply the law of conservation of energy, which states that energy cannot be created nor destroyed.

Therefore, the total gravitational potential energy of the skier has to be equal to the total kinetic energy of the skier.

The formula for gravitational potential energy (U) is given as:

U = mgh, where:

m is the mass of the object

g is the acceleration due to gravity

h is the vertical height at which the object is placed

The formula for kinetic energy (K) is given as:

K = ½mv², where:

m is the mass of the object

v is the velocity (or speed)

U = K

mgh = ½mv²

Let’s cancel the m’s on both sides:

gh = ½v²

Now, substitute the given values. We know that the acceleration due to gravity on Earth is 9.81 m/s², so g = 9.81. We are also given that the height of the hill is 27 m, so h = 27.

(9.81)(27) = ½v²

Solve for v:

264.87 = ½v²

529.74 = v²

v = 23.016

The velocity of the skier when they reach the bottom of the hill is 23.016 m/s.

Learn more about the law of conservation of energy here: brainly.com/question/166559