[tex]\bf \qquad \textit{parabola vertex form}\\\\
\begin{array}{llll}
y=a(x-{{ h}})^2+{{ k}}\\\\
\boxed{x=a(y-{{ k}})^2+{{ h}}}
\end{array} \qquad\qquad vertex\ ({{ h}},{{ k}})\\\\
-------------------------------\\\\
\begin{cases}
h=4\\
k=-3
\end{cases}\implies x=a(y-(-3))^2+4\implies x=a(y+3)^2+4[/tex]
