contestada

In the following reaction, what element is made?
241/95Am + 4/2He --> A/Z ? + 1/0n
A. 244/97 Bk
B. 245/97 Bk
C. 244/93 Np
D. 245/94 Np

In the following reaction what element is made 24195Am 42He gt AZ 10n A 24497 Bk B 24597 Bk C 24493 Np D 24594 Np class=

Respuesta :

kepasa
The correct answer is A. 244/97 Bk 

Answer: The correct answer is option (A).

Explanation:

General representation of an element:[tex]^{A}_ZX[/tex]

A= Atomic mass of the element of X.

Z = Atomic number of the element of X

X = symbol of the element.

[tex]^{241}_{95}Am+^{4}_2He\rightarrow ^{A}_ZX+^{1}_0n[/tex]

According to Law of Conservation of Mass:

[tex]241+4=A+1[/tex]

A = 244

Charge is balanced on both the sides:

[tex]95+2=Z+0[/tex]

Z = 97

The element with the atomic number 97 is Berkelium. Hence, the correct answer is option (A).