The volume of the given solid inside and outside the sphere is gotten as; E = 64π√6
Inside the sphere is; x² + y² + z² = 25
Outside the Sphere is; x² + y² = 1
Let E be the solid described above. Thus;
x = r cos θ; y = r cos θ; z = z
Volume(E) = ∫∫[tex]\int\limits^._E {1} \, dx[/tex]
Using double integral calculator and integrating through the following boundaries;
First boundary; Upper is √(25 - r²) and lower boundary is -√(25 - r²)
Second boundary; Upper is 5 and lower boundary is 1
Third boundary; Upper is 2π and lower is 0
This gives us;
Volume(E) = 64π√6
Read more about Double Integrals at; https://brainly.com/question/19053586
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