Using the ASCII code 219, print a white block on the screen. Using the up/down keys on the keyboard, the user can change the color of the block. - Once the 'Enter' key is pressed, the block takes its final color and a new block appears. The whole process repeats itself. - Once the user hits the 'Space' key, a list is printed showing the count of each color as follows: - Green Blocks: 2 - White Blocks: 2 - Red Blocks: 2 - Blue Blocks: 2 - Yellow Blocks: 2 - The code should provide a minimum of 5 colors for the user to choose from - The process is repeated indefinitely until the 'Space' key is pressed - If the first line is filled with blocks, a new block should be appended in a new line
Using 8086 assembly

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Shallipoi Shallipoi · Answer 1 · 2024-01-13T16:55:14+01:00

Answer:

section .data

color_count db 0, 0, 0, 0, 0 ; Green, White, Red, Blue, Yellow

current_color db 219 ; Initial color

section .text

global _start

_start:

; Initialize your environment and set up the screen

loop_blocks:

; Print the block in the current color at the current position

; Wait for user input (up/down keys to change color, enter to finalize, space to print count)

; Handle user input and update variables accordingly

; Check if the line is filled, and if so, move to the next line

; Repeat until the 'Space' key is pressed

; Print the color count list

; Terminate the program