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There are three resistors in a circuit with an applied voltage of 120V. The voltage drop across two of the resistors is 20V each. What is the voltage drop across the third resistor?

Respuesta :

Answer:

If m=a~cos~\theta+b~sin~\theta and n=a~sin~\theta-b~cos~\theta then prove that m^{2}+n^{2}=a^{2}+b^{2}

Explanation:

the answer is 80 V......

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