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The cyclist starts moving in a calm state and moves in a straight line and with uniform acceleration. 10 s after the start of movement, its speed is 2 m/s. How fast was the cyclist moving?
1) 0.2 m/s2; 2) 2 m/s2; 3) 2.5 m/s2; 4) 10 m/s2.

Respuesta :

Answer: a) 0.2 m/s²

Explanation:

The relationship between initial velocity (v₀), acceleration (a), time (t), and final velocity (v) is given by the kinematic equation:

v = v₀ + at

In this case, the cyclist starts from rest since the problem states "after the start of movement" (v₀ = 0), and after 10 seconds (t = 10), the velocity is 2 m/s (v = 2).

Plugging these values into the equation above:

v = v₀ + at

2 = 0 + a·10

Solving for a, we get:

2 = 10a

a = 2/10

a = 0.2

The cyclist's acceleration is 0.2 m/s².

Learn more about kinematics here: https://brainly.com/question/26407594