To solve this problem,
we can use the Henderson-Hasselbalch Equation which relates the pH to the measure
of acidity pKa. The equation is given as:
pH = pKa + log ([base]/[acid]) ---> 1
Where,
[base] = concentration of C2H3O2 in molarity or moles
[acid] = concentration of HC2H3O2 in molarity or moles
For the sake of easy calculation, let us assume that:
[base] = 1
[acid] = x
Therefore using equation 1,
4.24 = 4.74 + log (1 / x)
log (1 / x) = - 0.5
1 / x = 0.6065