Answer:
Step-by-step explanation:
Given that the radius of a sphere originally r is halved. We have to find the new volume of the sphere.
Volume of the sphere = [tex]\frac{4}{3} \pi r^3[/tex]
When radius is halved new radius = r/2
Hence volume of the reduced sphere
=[tex]\frac{4}{3}\pi (\frac{r}{2} )^3=\frac{1}{8} \frac{4}{3}\pi r}^3\\=\frac{1}{8} V[/tex]
Volume becomes 1/8 times of the original volume.
