Respuesta :
CS₂ + 3O₂ = CO₂ + 2SO₂
n(CS₂)=2 mol
V₀=22.4 L/mol
V(SO₂)/2V₀=n(CS₂)
V(SO₂)=2V₀n(CS₂)
V(SO₂)=2*22.4*2=89.6 L
n(CS₂)=2 mol
V₀=22.4 L/mol
V(SO₂)/2V₀=n(CS₂)
V(SO₂)=2V₀n(CS₂)
V(SO₂)=2*22.4*2=89.6 L
Answer: 98.6 Litres
Explanation: From the given chemical equation :
CS2 + 3O2 → CO2 + 2SO2
From the equation above,
1 mole of CS2 gas produces 2 moles of SO2 gas
Therefore,
2 moles of CS2 gas will produce (2*2) moles of SO2 gas
= 4 moles of SO2 gas
Also at STP,
The volume of 1 mole of gas is 22.4 Litres
Hence,
The volume of 4 moles of SO2 gas produce will be
22.4*4 Litres
= 98.6 Litres
Hence, the volume of SO2 gas produce from 2 moles of CS2 in the given reaction at STP is 98.6 Litres.
