Respuesta :
Answer: l=0, m= -2, m=2 are all valid.
Explanation: The given value on n =3, that is the principal quantum number or the main energy level for the electron is 3 i.e. M shell.
For a given value of n, the possible values of azimuthal quantum number (l) are 0 to n-1.
Thus possible values of l are = 0, 1 , 2
Also for a given value of l, the possible values of magnetic quantum number (m) are = l to -l
Thus for l=0 possible values of m is 0 , for l = 1 possible values of m are -1, 0 and 1 , for l= 2 possible values of m are -2, -1, 0, 1, 2
For the n = 3 electron shell, the following quantum numbers are valid;
- l = 0
- m = –2
- m = 2
Quantum numbers are used to describe the position of an electron in an atom.
There are four sets of quantum numbers;
- Orbital quantum number (l)
- Principal quantum number (n)
- Magnetic quantum number (m)
- Spin quantum number (s)
For an electron in orbital n=3, the possible values of l are 0 to 2. The possible values of m are -2, -1, 0, 1, 2.
Hence;
- l = 0
- m = –2
- m = 2
Are valid quantum numbers for that electron.
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