Respuesta :

we know that

In the right triangle ABC

m∠A+m∠B=[tex]90\°[/tex] --------> by complementary angles

m∠A=[tex]90\°[/tex]-m∠B --------> equation [tex]1[/tex]

so

[tex]sin (B)=\frac{b}{c}\\\\cos (A)=\frac{b}{c}[/tex]

[tex]sin(B)=cos(A)[/tex] -------> equation [tex]2[/tex]

substitute equation [tex]1[/tex] in equation [tex]2[/tex]

[tex]sin(B)=cos(90-B)[/tex]

therefore

the answer is the option

sin(B) = cos(90 – B)

The sum of the all the angle in a triangle is equal to the 180 degrees.

The relationship which is true for the given triangle is,

[tex]\sin (B)=\cos (90-B)[/tex]

Thus the option B is the correct option.

What is the value of sine in right angle triangle?

In a right angle triangle the ratio of opposite side to the hypotenuse side is equal to the angle of sine.

Given information-

The given triangle in the figure [tex]\Delta ABC[/tex] is right angle triangle.

[tex]m\angle C[/tex] is the right angle measure of 90 degrees.

The sum of the all the angle in a triangle is equal to the 180 degrees. Thus,

[tex]m\angle C+m\angle A +m\angle B=180[/tex]

Put the value of [tex]m\angle C[/tex] as,

[tex]90+m\angle A +m\angle B=180\\m\angle A +m\angle B=180-90\\m\angle A +m\angle B=90[/tex]

Thus the sum of measure of  [tex]m\angle A[/tex] and [tex]m\angle B[/tex] is 90 degrees.

Solve further as,

[tex]m\angle A =90-m\angle B[/tex]

Let the above equation as equation number 1.

In a right angle triangle the ratio of opposite side to the hypotenuse side is equal to the angle of sine. Thus,

[tex]Sin(B)=\dfrac{b}{c}[/tex]

Similarly,

[tex]\cos(A)=\dfrac{b}{c}[/tex]

Hence for the right angle triangle,

[tex]\sin (B)=\cos (A)[/tex]

Put the value of angle form equation 1 to the above equation as,

[tex]\sin (B)=\cos (90-B)[/tex]

Hence the relationship which is true for the given triangle is,

[tex]\sin (B)=\cos (90-B)[/tex]

Thus the option B is the correct option.

Learn more about the right angle triangle here;

https://brainly.com/question/64787

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