A concession-stand manager buys bottles of water and soda to sell at a football game. The manager needs to buy a total of 4,500 drinks and have 25% more water than soda. Let w be the number of bottles of water and let s be the number of bottles of soda. Create a system of equations for w in terms of s that the manager could use to find out how many bottles of water and soda to buy.

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judypatootie judypatootie · Answer 1 · 2017-06-10T17:49:12+02:00

w + s = 4500 and w = s + .25s

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jajumonac jajumonac · Answer 2 · 2020-01-30T02:07:36+01:00

Answer:

Step-by-step explanation:

From the problem we know that the manage needs to buy a total of 4,500 drinks between water and soda, this can be expressed as

[tex]w+s=4500[/tex]

Where [tex]w[/tex] is water and [tex]s[/tex] is soda.

Then, it's given that there is needed 25% more water than soda, which can be expressed as

[tex]w=s+0.25s=1.25s[/tex]

Which means that water represents 125% of the soda, because we must include the additional 25% more water over soda.

Then, we replace the second relation into the first one

[tex]w+s=4500\\1.25s+s=4500\\2.25s=4500\\s=\frac{4500}{2.25}=2000[/tex]

Now, we replace this value in one equation to obtain the other one

[tex]w+2000=4500\\w=4500-2000\\w=2500[/tex]

Therefore, the manager has to by 2,000 sodas and 2,500 water drinks.