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Eli has 7 black pens and 5 blue pens in his desk drawer. he also has 3 yellow highlighters, 2 green highlighters, and 5 pink highlighters in his pencil case. If he chooses one pen and one highlighter without looking, what is the probability that he will get a black pen and he will not get a green highlighter?

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joshrans
7/22 or 31% chance of getting black pen
2/22 or 9% chance he will not get a green highlighter

Answer:

The probability is 7/15.

Step-by-step explanation:

Total number of pens = 7+5 = 12

Out of 12, 7 are black and 5 are blue pens.

Similarly, total number of highlighters = 3+2+5 = 10

Out of 10, 3 are yellow highlighters, 2 are green highlighters, and 5 are pink .

Now, Eli is choosing one pen and one highlighter without looking, so the probability that he will get a black pen and he will not get a green highlighter will be = [tex]\frac{7}{12}\times\frac{8}{10}[/tex]

= [tex]\frac{7}{15}[/tex]

Hence, the probability is 7/15 or 46.66%.

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