Respuesta :
[tex]\bf sin(x)\approx 0.2588\implies \measuredangle x \approx sin^{-1}(0.2588)\\\\
-----------------------------\\\\
sin\left(\frac{\pi}{2}-{{ \theta}}\right)=cos({{ \theta}})\qquad
cos\left(\frac{\pi}{2}-{{ \theta}}\right)=sin({{ \theta}})\leftarrow
\begin{array}{llll}
complementary\\
angles
\end{array}\\\\
-----------------------------\\\\
thus\qquad cos\left( \frac{\pi }{2}-x \right)=sin(x)\approx 0.2588[/tex]
